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28
Oct
2020
Find and replace
28 Oct 2020
Find: (:update\s.*)(_new) Replace: $1 Given text: foo:update example_new foo:update word_new foo:update also_new Output: foo:update example foo:update word foo:update also
ide
regex
5
Feb
2019
regex
05 Feb 2019
select column ^.{12}\K(.){10}
regex
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