28
Oct
2020

Find and replace

28 Oct 2020
Find: (:update\s.*)(_new) Replace: $1 Given text: foo:update example_new foo:update word_new foo:update also_new Output: foo:update example foo:update word foo:update also
5
Feb
2019

regex

05 Feb 2019
select column ^.{12}\K(.){10}